20 ml of 0.4 M H2SO4 and 80 ml of 0.2 M NaOH are mixed. Then the pH of the resulting solution is
On mixing, the following reaction take place
H2SO4 | + | 2NaOH | Na2SO4+2H2O | |
Milli moles | = 20 x 0.4 | 80 x 0.2 | ||
= 8 | 16 |
Since there is no limiting reagent, acid and base will be completely neutralised.
PH of a neutral salt (Na2SO4) solution is 7.