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Q.

A 100 mL, 0.1 M solution of ammoniurn acetate is diluted by adding 100 mL of water. The pH of the resulting solution will be (pKa of acetic acid is nearly equal to pKb of NH4OH )

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a

4.9

b

5.9

c

7.0

d

10.0

answer is C.

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Detailed Solution

Ammonium acetate is a salt of weak acid and weak base. When solutions are of weak acid and weak base, pH of solution is calculated from the following relationship.pH=7+12pKa-12pKbor pKa≈pKb( given )∴ pH of solution = 7
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