First slide

Gaseous state

Question

A 4 : 1, molar mixture of He and CH₄ is contained in a vessel at 2O bar pressure. Due to a hole in the vessel, the gas mixture leakes out. The composition of the mixture effusing out initally is x : 1. What is the value of x?

Moderate

Solution

$\frac{r_{H_{2}}}{r_{C H_{4}}} = \frac{n_{H_{2}}}{n_{{CH}_{4}}} \sqrt{\frac{M_{C H_{4}}}{M_{H_{2}}}} = \frac{4}{1} \sqrt{\frac{16}{4}} = 8$
Initial ratio of rates of effusion gives the initial composition of mixture effusing out. Therefore n(He) : n(CH₄) = 8 : 1.
The value of x is 8.

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