A 4 : 1, molar mixture of He and CH4 is contained in a vessel at 2O bar pressure. Due to a hole in the vessel, the gas mixture leakes out. The composition of the mixture effusing out initally is x : 1. What is the value of x?
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answer is 8.
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Detailed Solution
rH2rCH4=nH2nCH4MCH4MH2=41164=8Initial ratio of rates of effusion gives the initial composition of mixture effusing out. Therefore n(He) : n(CH4) = 8 : 1.The value of x is 8.