4 mole of NH₄OH and 1 mole of H₂SO₄ are mixed and diluted to 1 lit solution. The pK_b of NH₄OH is 4.8 . The pH of solution is

Moderate

Solution

Following reaction will occur
2NH₄OH + H₂SO₄
$\large \rightarrow$
(NH₄)₂SO₄ + 2H₂O
t = 0 4 mol 1 mol 0 0
$\large t=t_\infty$
(4 - 2) mol (1 - 1) mol 1 mol 2 mol
= 2 mol 0 mol
NH₄OH is monovalent whereas (NH₄)₂SO₄ is bivalent;
P^OH = P^K_^b + $\log \frac{1 \times 2}{2};$
P^OH = 4.8
P^H = 14 - 4.8 = 9.2

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