N2+3H2⟶2NH3 1 mole N2 and 4 moles H2 are taken in 15 L flask at 27°C. After complete conversion of N2 into NH3, 5 L of H2O is added. Pressure set up in the flask is

N2+3H2⟶2NH3Taken           1      4            0Reacts          1     3  H2 Ieft = 1 mol NH3 formed = 2 mol but NH3(g) dissolves in water forming NH4OH. Residual gas is only H2 which exerts pressure.Volume = 15 - 5 = 10 L (5 L is occupied by H2O added)∴ p=nVRT=1×0.0821×30010atm