First slide

Enthalpy of formation

Question

P_4(g) → P_4(s), ΔH=-59 KJ; P_4(g)+5O₂(g) → P₄O_10(s), ΔH = ? [ ΔH_f (P₄O₁₀) = -2984 KJ]

Easy

A

+3043 KJ
B

-3043 KJ
C

-2925 KJ
D

-2984 KJ

Solution

$= Δ_{f} H_{p_{4} O_{10}} - [Δ_{f} H_{p_{4}} + 5 Δ_{f} H_{O_{2}}]$ P_4(s)→P_4(g) ΔH = +59
P_4(g) +5O_2(g)→P₄O_10(s)
$Δ_{r} H = \sum Δ_{f} H_{p} - \sum Δ_{f} H_{R}$ $= Δ_{f} H_{p_{4} O_{10}} - [Δ_{f} H_{p_{4}} + 5 Δ_{f} H_{O_{2}}]$
= -2984 -[+59+5(0)]
= -2984-59
= -3043 KJ

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