First slide

PH of strong acids and strong bases

Question

$p^{H}$ of 0.01M $NaOH$ solution is ‘X’ & 0.05M $H_{2} {SO}_{4}$ is ‘Y’. Value of (X–Y) is equal to

Easy

Solution

$[{OH}^{-}] = (0 .01 M) 1$
$p^{OH} = 2$
$p^{H} = 12$
$[H^{+}] = (0 .05 \times 2) M$
$p^{H} = 1; X - Y = 11$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App