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Q.

The pH 0.005 M codeine (C18H21NO3) solution is 995. Its pKb value is

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a

8.92

b

5.81

c

3.76

d

4.29

answer is B.

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Detailed Solution

C18H21NO3 +H2O  ⇌  Codeine H+ +OH-pH=9.95   POH =14-9.95= 4.05POH = -log[ OH-]log[ OH-]= -4.05= 5¯.95OH-= antilog  5¯.95 = 8.913×10-5Kb= Codeine H+OH-[Codeine ]=OH-2[ Codeine ]Kb=8.913×10-520.005=1.588×10-6pKb=-logKb = -log 1.588×10-6pKb=6 + (-0.2009)=5.7791≈5.80≈5.81
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