First slide

PH of strong acids and strong bases

Question

The pH of a solution is 3.602. Its H⁺ ion concentration is

Easy

A

$4 \times 10^{- 14}$
B

$2.5 \times 10^{- 11}$
C
$2.5 \times 10^{- 4}$
D

$5.0 \times 10^{- 4}$

Solution

Let the [H⁺] be, a x 10^-b
Then P^H = b - log a = 3.60
⇒ b - log a= 3.60 = 4 - 0.398
b = 4
log a = 0.398
log 2.5 = 0.398
[H⁺] = 2.5 x10^-4

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