First slide

PH of strong acids and strong bases

Question

The pH of a solution is 4.301. To 50 ml of this solution 200 ml of water is added. Then the pH of resulting solution is

Moderate

A

4.9
B

5.301
C

5.7
D

5.0

Solution

[H⁺] = 10^-4.3
${[H^{+}]}_{final} = \frac{10^{- 4.3} \times 50}{250} = 2 \times 10^{- 4.3 - 1}$
${[H^{+}]}_{final} = 2 \times 10^{- 5.3}$
P^H = 5.3 - log 2 =5

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