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Q.

The pKb for fluoride ion at 25°C is 10.83, the ionisation constant of hydrofluoric acid at this temperature is

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a

2.72×10-5

b

3.52×10-3

c

6.76×10-4

d

5.38×10-2

answer is C.

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Detailed Solution

F-+H2O⇌HF+OH-Kb=[HF]OH-F-Kw=H3O+OH-=10-14Dissociation of HF in water is represented by the equation,HF+H2O⇌H3O++F-Ka= H3O+F-[HF]-----------(iii)Kb·Ka=H3O+OH-=Kwor KwKb=KaTaking log on both sideslogKa= logKw-logKb          =-pKw+logKb          =-14+10.83=-3.17     Ka= 6.76×10-4
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