The pKb for fluoride ion at 25°C is 10.83, the ionisation constant of hydrofluoric acid at this temperature is
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
a
2.72×10-5
b
3.52×10-3
c
6.76×10-4
d
5.38×10-2
answer is C.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
F-+H2O⇌HF+OH-Kb=[HF]OH-F-Kw=H3O+OH-=10-14Dissociation of HF in water is represented by the equation,HF+H2O⇌H3O++F-Ka= H3O+F-[HF]-----------(iii)Kb·Ka=H3O+OH-=Kwor KwKb=KaTaking log on both sideslogKa= logKw-logKb =-pKw+logKb =-14+10.83=-3.17 Ka= 6.76×10-4