First slide

Alkynes

Question

The ratio of sp and sp3 orbitals present in the product formed from the reaction between 1,1,5,5–tetrabromopentane and sodamide?

Difficult

A

1
B

2
C

3.5
D

2.5

Solution

1,1,5,5–tetrabromopentane will undergo dehydrohalogenation reaction in the presence of and forms penta–1,4–diyne. penta–1,4–diyne is having 4 sp and 1 sp3 carbon.
$\begin{array}{l} Each sp carbon is having two sp orbitals \\ {each sp}^{3} {carbon is having four sp}^{3} orbitals. \\ {The ratio of sp and sp}^{3} orbitals is \frac{4 \times 2}{1 \times 4} = \frac{8}{4} = 2 \end{array}$

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