First slide

Gibb's Helmholtz equation

Question

For a reaction R₁ , $\large \Delta G\,=\,x\,\,KJ\,\,mo{{l}^{-1}}.$ For a reaction R₂ , $\large \Delta G\,=\,y\,\,KJ\,\,mo{{l}^{-1}}.$
Reaction R₁ is non-spontaneous but along with R₂ it is spontaneous. This means that

Easy

A

x is -ve , y is +ve but in magnitude x > y
B

x is +ve, y is -ve but in magnitude y > x
C

Both x and y are -ve but not equal
D

Both x and y are +ve but not equal.

Solution

A process is non spontaneous means $∆ G = + ve;$
Thus for $R_{1}, ∆ G = x = + ve; But for R_{2} ∆ G = y = - ve because it is spontaneous; R_{1} becomes spontaneous in presence of R_{2}, this is possible only when magnitude of y > x;$

Such reactions are known as coupling reactions.

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