R-I : NH3+BF3 → H3N→BF3R-II : NH3+H+ →NH4+Correct statements about R-I and R-II areA) NH3 is a Lewis base in both R-I and R-IIB) NH3 is a B-L base in both R-I and R-IIC) NH3 is a Lewis base only in R-ID) NH3 is a Lewis base only in R-IIE) NH3 is a B-L base only in R-IIF) NH3 is a B-L base only in R-I
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a
A, B, C, D, E, F
b
A, E only
c
B, D only
d
A, C, D, F only
answer is B.
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Detailed Solution
I) In R-I…. N..H3 donates lone pair to BF3 and thus acts like Lewis base. In this reaction NH3 is not a proton acceptor. It is not a B-L baseII) In R-II… N..H3 donates lone pair to H+ (proton) ;It is an electron pair donar and a proton acceptor.Thus it acts like Lewis base and a B-L base.
R-I : NH3+BF3 → H3N→BF3R-II : NH3+H+ →NH4+Correct statements about R-I and R-II areA) NH3 is a Lewis base in both R-I and R-IIB) NH3 is a B-L base in both R-I and R-IIC) NH3 is a Lewis base only in R-ID) NH3 is a Lewis base only in R-IIE) NH3 is a B-L base only in R-IIF) NH3 is a B-L base only in R-I