First slide

Solubility product(KSP)

Question

The solubility of PO₄^–3 is ‘x’ m/l in Ca₃(PO₄)₂. Then its K_sp is

Moderate

A

108x⁵
B

32x⁵
C

$\frac{8}{27} x^{5}$
D

$\frac{27}{8} x^{5}$

Solution

${Ca}_{3} {({PO}_{4})}_{2} (s) ⇌ \underset{s}{{Ca}_{3} {({PO}_{4})}_{2}} (a q) \to \underset{3 s}{3 {Ca}^{+ 2}} (a q) + \underset{2 s}{2 {PO}_{4}^{- 3}} (a q)$
2S = x
K_sp = (3S)³ x (2S)² = 108 S⁵
$K_{sp} = 108 \times {(\frac{x}{2})}^{5} = \frac{27}{8} x^{5}$

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