Solubility product of AgCl is 2.8 × 10-10  at 250C. Calculate solubility of the salt in 0.1 M AgNO3 solution

In 0.1 M AgNO3AgNO3  ⇌   Ag+ + NO3- AgCl  ⇌   Ag+ + Cl -KSP   =   Ag+  Cl - 2.8×10-10 =[0.1] [Cl-]  Ag+ can be taken as  AgNO3 ∴   Solubility of AgCl =  2.8×10-1010-1                                            =2.8×10-9 moles/lit