First slide

Solubility product(KSP)

Question

Solubility product of AgCl is $2.8 \times 10^{- 10} at 25^{0} C .$ Calculate solubility of the salt in 0.1 M ${AgNO}_{3}$ solution

Moderate

A

$2.8 \times 10^{- 9} mol / litre$
B

$2.8 \times 10^{- 10} mol / litre$
C

$3.2 \times 10^{- 9} mol / litre$
D

$3.2 \times 10^{- 12} mol / litre$

Solution

In 0.1 M $A g N O_{3}$
${AgNO}_{3} ⇌ {Ag}^{+} + {NO}_{3}^{-^{}}$
$AgCl ⇌ {Ag}^{+} + {Cl}_{}^{-}$
$K_{S P} = [A g^{+}] [C l_{}^{-}] 2.8 \times 10^{- 10} = [0.1] [{Cl}^{-}]$
$[A g^{+}]$ can be taken as $[A g N O_{3}]$
$∴ Solubility of AgCl = \frac{2.8 \times 10^{- 10}}{10^{- 1}} = 2.8 \times 10^{- 9} moles / lit$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App