First slide

Solubility product(KSP)

Question

The solubility of a sparingly soluble salt ${AB}_{2}$ in water is $1.0 \times 10^{- 5} mol L^{- 1} .$ Its solubility product is

Easy

A

$10^{- 5}$
B

$10^{- 10}$
C

$4 \times 10^{- 15}$
D

$4 \times 10^{- 10}$

Solution

$K_{SP} = 4 S^{3} = 4 \times {(10^{- 5})}^{3} = 4 \times 10^{- 15} M^{3}$

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