First slide

Basic Buffer

Question

A solution consists of 0.2 M NH₄OH and 0.2 M NH₄Cl. If K_b of NH₄OH is 1.8 × 10^–5, the [OH^–] of the resulting solution is

Moderate

A

$0.9 \times 10^{- 5} M$
B

$1.8 \times 10^{- 5} M$
C

$3.2 \times 10^{- 5} M$
D

$3.6 \times 10^{- 5} M$

Solution

P^OH of a basic buffer is give as $P^{OH} = P^{K_{b}} + \log \frac{[salt]}{[base]}$
P^OH = 4.76 + log $\frac{0.2}{0.2}$
P^OH = 4.76
[OH^-] = 1.8 x 10^-5 M

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