First slide

Acidic buffer

Question

A solution contains equimolar concentration of a weak acid HA and its conjugate base A^–. pKb of A^–is 9. The pH of the solution is

Easy

A

9
B

5
C

7
D

5.301

Solution

P^Hof an acidic buffer is given as, $P^{H} = P^{Ka} + \log \frac{[Salt]}{[Acid]}$
Also for a conjugate acid-base pair , $P^{Ka} + P^{Kb} = P^{Kw}$
$P^{Ka} = 14 - 9 = 5$
From first equation, $P^{H} = 5 + 0 = 5$

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