First slide

Solubility product(KSP)

Question

Three sparingly soluble salts $M_{2} X, MX and {MX}_{3}$ have the same solubility product. Their solubilities will be in the order

Moderate

A

${MX}_{3} > MX > M_{2} X$
B

${MX}_{3} > M_{2} X > MX$
C

$MX > {MX}_{3} > M_{2} X$
D

$MX > M_{2} X > {MX}_{3}$

Solution

$M_{2} X \to 2 M^{+} + X^{-_{}}$
$2 s_{1} s_{1} K_{sp} = 4 {s_{1}}^{3} or, s_{1} = {(K_{sp} / 4)}^{1 / 3} MX \to M^{+} + X^{-}, K_{sp} = s_{2}^{2} or, s_{2} = {(K_{sp})}^{1 / 2} {MX}_{3} \to M^{3 +} + 3 X^{-} s 3 s K_{sp} = 27 s_{3}^{4} or, s_{3} = {(K_{sp} / 27)}^{1 / 4} Evidently, s_{3} > s_{1} > s_{2} Alternately Different sparingly soluble salts having same solubility product, salt which produces more number of ions will have more solubility .$

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