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Q.

van der Waals' equation for calculating the pressure of a non ideal gas isP+an2V2(V−nb)=nRTvan der Waals' suggested that the pressure exerted by an ideal gas, Pideal, is related to the experimentally measured pressure, Preal by the equationPideal =Preal +an2V2 ↑ ↑   observed correction  pressure term      Constant 'a' is measure of intermolecular interaction between gaseous  molecules that gives rise to non-ideal behavior. It depends upon how frequently any two molecules approach each other closely. Another correction concerns the volume occupied by the gas molecules. In the ideal gas equation, V represents the volume of the container. However, each molecule does occupy a finite, although small, intrinsic volume, so the effective volume of the gas becomes (V - nb), where n is the number of moles of the gas and b is a constant. The term nb represents the volume occupied by gas particles present in n moles of the gas. Having taken into account the corrections for pressure and volume, we can rewrite the ideal gas equation as followP+an2V2(V−nb)=nRT corrected  corrected  pressure  volume At relatively high pressures, the van der Waals' equation of state reduces toFor non-zero value of force of attraction between gas molecules at large volume, gas equation will be: The van der Waals' constant 'a' for CO2 gas is greater than that of H2 gas. Its mean that the

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answer is [OBJECT OBJECT], [OBJECT OBJECT], [OBJECT OBJECT].

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Detailed Solution

p+aVm2Vm−b=RTP↑↑⇒Vm↓↓ P+aVm2≈pPVm−b=RTPVm=RT+PbV↑↑⇒P↓↓V−nb≈VP+n2aV2V=nRTPV+n2aV=nRTPV=nRT−n2aV van der Waal's constant ' a ' ∝ I. M. A.F. So CO2 gas can be more easily liquified.
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