First slide
Gaseous state
Question

van der Waals' equation for calculating the pressure of a non ideal gas is

P+an2V2(Vnb)=nRT

van der Waals' suggested that the pressure exerted by an ideal gas, Pideal, is related to the experimentally measured pressure, Preal by the equation

Pideal =Preal +an2V2     observed correction  pressure term      

Constant 'a' is measure of intermolecular interaction between gaseous  molecules that gives rise to non-ideal behavior. It depends upon how 
frequently any two molecules approach each other closely. Another correction concerns the volume occupied by the gas molecules. In the ideal gas equation, V represents the volume of the container. However, each molecule does occupy a finite, although small, intrinsic volume, so the effective volume of the gas becomes (V - nb), where n is the number of moles of the gas and b is a constant. The term nb represents the volume occupied by gas particles present in n moles of the gas. Having taken into account the corrections for pressure and volume, we can rewrite the ideal gas equation as follow

P+an2V2(Vnb)=nRT corrected  corrected  pressure  volume 

Moderate
Question

At relatively high pressures, the van der Waals' equation of state reduces to

Solution

p+aVm2Vmb=RTP↑↑⇒Vm↓↓ P+aVm2pPVmb=RTPVm=RT+Pb

Question

For non-zero value of force of attraction between gas molecules at large volume, gas equation will be: 

Solution

V↑↑⇒P↓↓VnbVP+n2aV2V=nRTPV+n2aV=nRTPV=nRTn2aV

Question

The van der Waals' constant 'a' for CO2 gas is greater than that of H2 gas. Its mean that the

Solution

 van der Waal's constant ' a '  I. M. A.F. 

So CO2 gas can be more easily liquified.

Get Instant Solutions
When in doubt download our app. Now available Google Play Store- Doubts App
Download Now
Doubts App