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Q.

A volume of 50.00 mL of a weak acid of unknown concentration is titrated with 0.10 M solution of NaOH. The equivalence point is reached after 39.30 mL of NaOH solution has been added. At the half-equivalence point (19.65 mL), the pH is 4.85. Thus, initial concentrations of the acid and its pKa values are

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a

[HA] initial              pKa0.1 M                     4.85

b

[HA] initial              pKa0.079 M                 2.93

c

[HA] initial              pKa0.1 M                     3.70

d

[HA] initial              pKa0.079 M                 4.85

answer is D.

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Detailed Solution

M1V1Acid = M2V2BaseM1 × 50.0 = 0.10 × 39.30 ∴    M1 = 0.10 × 39.3050 = 0.0786 MWhen half-equivalence point is reachedHA = A-pH = pKa + log   A-HA∴     pH = pKa =   4.85
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