First slide

PH of strong acids and strong bases

Question

What is the pH of a solution obtained by dissolving 0.0005 mole of the strong electrolyte, calcium hydroxide, Ca(OH)₂ to form 100 ml of a saturated solution (aqueous)?
(K_w = 1.0 × 10^–14 mole²litre^–2)

Moderate

A

9.8
B

11.7
C

12.0
D

3.0

Solution

$[Ca (OH)_{2}] = \frac{5 \times 10^{- 4}}{100 \times 10^{- 3}}$
$∴ [O H^{-}] = \frac{2 \times 5 \times 10^{- 1}}{100} = 10^{- 2}$
[H⁺] = 10^-12
P^H = 12

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