First slide

Solubility product(KSP)

Question

What will be the molar solubility S of a solid salt with general formula $M_{x}^{p +} X_{y}^{q -}$ ?

Moderate

A

${(\frac{K_{sp}}{x^{y} \cdot y^{x}})}^{1 / x + y}$
B

${(\frac{K_{sp}}{x^{x} \cdot y^{y}})}^{x + y}$
C

${(\frac{K_{sp}}{x^{x} \cdot y^{y}})}^{1 / x + y}$
D

${(\frac{K_{sp}}{x^{y} \cdot y^{x}})}^{x + y}$

Solution

A solid salt,of the general formula, $M_{x}^{p +} X_{y}^{q -}$ with molar solubility ,S in equilibrium with its saturated solution may be represented by the equation,
$M_{x} X_{y} (s) ⟶ {xM}^{p +} (aq) + {yX}^{q -^{'}} (aq)$
$(where x \times p^{+} = y \times q^{-})$
$(where x \times p^{+} = y \times q^{-})$
And its solubility product constant is given by
$K_{sp} = {[M^{p +}]}^{x} {[X^{q -}]}^{y} = (xS)^{x} (yS)^{y}$
$K_{SP} = x^{x} \cdot y^{y} \cdot S^{(x + y)}$
$S^{(x + y)} = \frac{K_{sp}}{X^{x}, Y^{y}} or S = {(K_{sp} / X^{x} \cdot Y^{y})}^{1 / x + y}$

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