What will be the molar solubility S of a solid salt with general formula Mxp+Xyq- ?
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
a
Kspxy·yx1/x+y
b
Kspxx·yyx+y
c
Kspxx·yy1/x+y
d
Kspxy·yxx+y
answer is C.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
A solid salt,of the general formula, Mxp+Xyq- with molar solubility ,S in equilibrium with its saturated solution may be represented by the equation,MxXy(s)⟶xMp+(aq)+yXq-'(aq) (where x×p+=y×q- (where x×p+=y×q-And its solubility product constant is given byKsp=Mp+xXq-y=(xS)x(yS)yKSP= xx·yy·S(x+y)S(x+y)=KspXx,Yy or S = Ksp/Xx·Yy1/x+y