When CO2 is bubbled in excess of water, the following equilibrium is established. CO2+2H2O⇌H3O++HCO3-Kc = 3.8×10–7, pH = 6. What would be the HCO3-CO2?
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a
6
b
0.0038
c
0.038
d
0.38
answer is D.
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Detailed Solution
Given equilibrium is ,CO2+2H2O⇌H3O++HCO3-Kc=H3O+HCO3-CO2⇒3.8×10-7=10-6×HCO3-CO2⇒HCO3-CO2=3.8×10-1