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Q.

When 11.2 g of KOH is added to one litre of 'X' M H2SO4 solution, the pOH of the solution becomes 13.301. Then the value of 'X' is (assume no change in the volume of solution by the addition of KOH)

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a

0.4

b

0.6

c

0.8

d

0.2

answer is D.

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Detailed Solution

Following reaction takes placeleft after neutralisation =2×11.256Given, POH = 13.3 ⇒ PH = 0.7⇒ [H+] = 2 ×10-1Thus,⇒ 2x = 4 ×10-1⇒ x = 2 ×10-1

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When 11.2 g of KOH is added to one litre of 'X' M H2SO4 solution, the pOH of the solution becomes 13.301. Then the value of 'X' is (assume no change in the volume of solution by the addition of KOH)