First slide

Enthalpy of neutralization

Question

When 1 litre of 1M HCl is mixed with 1 litre of 1M NaOH, the rise in temperature was found to be T₁. In another experiment 1 litre of 0.5 M NaOH is mixed with 1 lit. of 0.5 M HCl. The rise in temperature was found to be T₂. Then

Moderate

Solution

ΔH = msΔT (s = specific heat)
No.of eq of acid/Base = 1x1 = 1eq
ΔH₁= -13.6=(1+1)ST₁......(1)
No.of eq of acid/base = 1x0.5=1/2eq
ΔH₂=-13.6/2=(0.5+0.5)ST₂......(2)
Dividing eq (1) and (2)

$\large \frac{{\Delta {H_1}}}{{\Delta {H_2}}}\; = \;\frac{{ - 13.6}}{{\frac{{ - 13.6}}{2}}}\; = \;\frac{{2S{T_1}}}{{S{T_2}}}\$

$\large \2 = \frac{{2{T_1}}}{{{T_2}}}\;\$

T₁=T₂

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