bag contains 20 coins. If the probability that the bag contains exactly 4 biased coin is 1/3 and that of exactly 5 biased coin is 2/3, then the probability that all the biased coin are sorted out from the bag in exactly 10 draws is
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a
510 16C6 20C9+111 15C5 20C9
b
233 16C6+515C5 20C9
c
533 16C7 20C9+111 15C6 20C9
d
none of these
answer is B.
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Detailed Solution
P(4 biased coin)=13P(5 biased coin)=14Hence, the required probability is=13 4C316C6 20C9+23 5C415C5 20C91 11C1=233 16C6+515C5 20C9