Let,f(x)=loglog1/3log7(sinx+a)be defined for every real value of x, then the possible value of a is
3
4
5
6
log1/3log7(sinx+a)>0 or 0<log7(sinx+a)<1 or 1<(sinx+a)<7,∀x∈R or 1−sinx<a<7−sinx
It is found that a should be less than the minimum value of(7 - sin x) and a must be greater than the maximum value of(1 - sin x). Thus,
⇒ 2<a<6