Six faces of a die are marked with numbers 1, –1, 0, –2, 2, 3 and the die is thrown thrice. The probability that the sum of the numbers thrown is six, is

Total number of cases is n(S) =63 =216 Suppose that E be the event of getting sum 6n(E) ={(2,2,2),(3,2,1),(3,1,2),(1,3,2),(3,3,0),(3,0,3),(0,3,3),(1,2,3),(2,1,3),(2,3,1)}      ∴n(E) =10 waysThe probability that the sum of the numbers thrown is six, is P(E) =10216