Suppose that z is a complex number that satisfies ∣z−2−2i∣≤1 The maximum value of |2iz+4| is equal to___________
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answer is 3.
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Detailed Solution
|z−2−2i|≤1denotes the region inside a circle with center (2, 2) and radius is 1|2iz+4|=|2i(z−2i)|=|2i||z−2i|=2|z−2i||z−2i|= _ distance of z from P(0,2)Hence, maximum value is 3.