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Q.

The vector z=3−4i  is turned anticlockwise through an angle of 1800  and stretched 2.5 times. The complex number corresponding to the newly obtained vector is:

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a

152−10i

b

−152+10i

c

−152−10i

d

None of these

answer is B.

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Detailed Solution

3−4i  i.e., (3,−4)  lie in fourth quadrant in complex plane, after turned anticlockwise through 1800  this will lie in II quadrant, therefore, the number will be −3+4i , now after stretching it 2.5 times i.e., multiplying by 2.5, the required complex number will be −152+10i .
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