First slide

Heat engine

Question

A Carnot cycle takes in 1000 J of heat from a source at a high temperature of 400 K. How much heat is rejected to the sink at a lower temperature of 300 K?

Moderate

A

0
B

250 J
C

500 J
D

750 J

Solution

$Efficiency of a carnot' s heat engine = η = 1 - \frac{Q_{2}}{Q_{1}} = 1 - \frac{T_{2}}{T_{1}} Q_{1} = Heat absorbed and Q_{2} = Heat rejected Q_{2} = Q_{1} (\frac{T_{2}}{T_{1}}) = 1000 (\frac{300}{400}) = 750 J$

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