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Q.

The circumference of the second Bohr orbit of electron in hydrogen atom is 600 nm. The potential difference that must be applied between the plates so that the electrons have the de Broglie wavelength corresponding in this circumference is

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a

10−5V

b

53×10−5V

c

5×10−5V

d

3×10−5V

answer is B.

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Detailed Solution

de Broglie wavelength of electron in hydrogen atom =hmv=2πrnnFor second Bohr orbit, λ=600×10−92=3000×10−9mλ=150VÅ=300Å∴ V=150(3000)2=53×10−5V

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