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Q.

Consider an YDSE that has different slits width. As a result, amplitudes of waves from two slits are A and 2A, respectively. If I0 be the maximum intensity of the interference pattern, then intensity of the pattern at a point where phase difference between waves is , is

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a

I0cos2ϕ

b

I03sin2ϕ2

c

I095+4cosϕ

d

I095+8cosϕ

answer is C.

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Detailed Solution

As amplitudes are A and 2A, so intensities would be in the ratio 1 : 4 Let us say I and 4I Imax=I0=l+4l+24l2=9l ⇒l=l09 Intensity at any point, l'=l+4l+24l2cosϕ ⇒l'=5l+4lcosϕ=I5+4cosϕ=l095+4cosϕ

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