First slide

Questions based on phase change

Question

5 g of ice at 0°C is mixed with 5 g of steam at 100°C. What is the final temperature of the mixture?

Moderate

A

200°C
B

400°C
C

300°C
D

100°C

Solution

Heat required by ice to raise its temperature to 100°C is
$Q_{1} = m_{1} L_{1} + m_{1} c_{1} {Δθ}_{1} = 5 \times 80 + 5 \times 1 \times 100$
= 400 + 500 = 900 cal
Heat given by steam, when condensed is
$Q_{2} = m_{2} L_{2} = 5 \times 540 = 2700 cal$
Since Q₂ > Q₁, it means that the whole steam is not even condensed. Hence, temperature of mixture remains at 100°C.

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