A galvanometer coil is replaced by another coil of diameter 1/4th of the original diameter and the total number of turns as ten times the original number. What will be the new deflection if the same current passes through it? Old deflection is θ.
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a
58θ
b
85θ
c
135θ
d
513θ
answer is A.
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Detailed Solution
For moving coil galvanometer, Cθ = NBAI Old Deflection = θ=NBAIC New Deflection = θ1=10NB(A/16)IC Dividing we get, θ1=58θ