First slide
First law of thermodynamics
Question

A gas is compressed at a constant pressure of 50 N/m2 from volume of 10 m3 to a volume of 4 m3 . Energy of 100 J is then added to the gas by heating. Its internal energy is

Moderate
Solution

Work done =P dV 
 dW=50×(410)=300J
Now dQ = dU + dW
 dU=dQdW=100+300=400J
Energy is increased by 400 J.

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