First slide
First law of thermodynamics
Question

An ideal gas undergoes the cyclic process abca as shown in the figure. The internal energy change of the gas along the path ca is -180 J. The gas absorbs 250 J of heat along the path ab and also absorbs 60 J of heat along the path bc. Find the work done by the gas along the path abc.

Moderate
Solution

ΔQ=ΔW+ΔU

250+60=ΔW+180

ΔW=130J

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