The intensity of light coming from one of the slits in Young's double slit experiment is double the intensity from the other slit. The ratio of maximum intensity to minimum intensity in the interference pattern will be

According to the given ProblemI1I2=a12a22=2  or  a1a2=2So, the amplitudes are in the ratio 2: 1 or amplitudes are2 and α For r maximum intensity (constructiveinterference), the resultant amplitude=(2+1)aFor minimum intensity (constructive interference)' the resultant amplitude =(2−1)aThis ratio of resultant intensities at maxima to that at minima =(2+1)2a2(2−1)2a2