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Q.

An inverted bell lying at the bottom of a lake 47.6 m deep has 50 cm3 of air trapped in it. The bell is brought to the surface of the lake. The volume of the trapped air will be (atmospheric pressure = 70 cm of Hg and density of Hg = 13.6 g/cm3)

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a

350 cm3

b

300 cm3

c

250 cm3

d

22 cm3

answer is B.

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Detailed Solution

According to Boyle's law, pressure and volume are inversely proportional to each other i.e. P∝1V⇒P1V1=P2V2⇒P0+hρwgV1=P0V2⇒V2=1+hρwgP0V1⇒V2=1+47.6×102×1×100070×13.6×1000V1⇒V2=(1+5)50cm3=300cm3. As P2=P0=70cm of Hg=70×13.6×1000

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An inverted bell lying at the bottom of a lake 47.6 m deep has 50 cm3 of air trapped in it. The bell is brought to the surface of the lake. The volume of the trapped air will be (atmospheric pressure = 70 cm of Hg and density of Hg = 13.6 g/cm3)