The inward and outward electric flux for a closed surface in units of N-m2/C are respectively 8 x 103 and 4 x 103. Then the total charge inside the surface is: [where ε0 = permittivity constant]
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a
4×103C
b
-4×103C
c
-4×103CεC
d
-4×103ε0C
answer is D.
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Detailed Solution
By Gauss's law ϕ=1ε0Qenclosed ⇒Qenclosed =ϕε0=−8×103+4×103ε0=−4×103ε0 coulomb.