A large open tank has two holes in the wall. One is a square hole of side L at a depth y from the top and the other is a circular hole of radius R at a depth 4 y from the top. When the tank is completely filled with water, the quantities of water flowing out per second from both holes are the same. Then, R is equal to
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a
L(2π)
b
2πL
c
L
d
L2π
answer is A.
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Detailed Solution
We know that rate of flow of water = y A, where y is the speed of efflux and A is area of cross section of the hole, Equating the rate of flow, we have(2gy)×L2=(2g×4y)πR2 L2=2πR2 or R2=L2/2π or R=L/(2π)