First slide
Change in internal energy
Question

One mole of diatomic ideal gas undergoes a cyclic process ABCA as shown in figure. The process BC is adiabatic. The temperatures at A,B and C are 400K, 800K and 600K respectively. Choose the correct statement :

Easy
Solution

Cv = fR/2

For diatomic gas, f = 5

\therefore {C_v} = \frac{{5R}}{2}

\therefore \Delta {U_{BC}} = {U_C} - {U_B} = 1\frac{{5R}}{2}\left( {600 - 800} \right)

= -500R

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