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Q.

A steel wire can support a maximum load of W before reaching its elastic limit. How much load can another wire, made out of identical steel, but with a radius one half the radius of the first wire, support before reaching its elastic limit?

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a

W

b

W2

c

W4

d

4W

answer is C.

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Detailed Solution

Breaking force = Breaking stress × Area of cross sectionFor a given material of the wire, breaking stress is constant.F1A1 = F2A2F2 = F1(A2A1) = F1(A14A1) = F14 = W4
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