First slide
Stress and strain
Question

A steel wire can support a maximum load of W before reaching its elastic limit. How much load can another wire, made out of identical steel, but with a radius one half the radius of the first wire, support before reaching its elastic limit?

Moderate
Solution

Breaking force = Breaking stress × Area of cross section

For a given material of the wire, breaking stress is constant.

F1A1 = F2A2

F2 = F1(A2A1) = F1(A14A1) = F14 = W4

Get Instant Solutions
When in doubt download our app. Now available Google Play Store- Doubts App
Download Now
Doubts App