First slide

First law of thermodynamics

Question

In a thermodynamic process the pressure of a fixed mass of gas is altered in such a manner that the gas releases out 20J of heat and at same time 8J of work is done on gas. The change in internal energy of gas is

Easy

A

12 J
B

20 J
C

- 12 J
D

- 20 J

Solution

$ΔU = Q - W = [(- 20) - (- 8)] J = - 12 J$

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