Three different processes that can occur in an ideal monoatomic gas are shown in the P vs V diagram. The paths are labeled as A→B,A→C and A→D . The change in internal energies during these process are taken as EAB,EAC and EAD and the work done as WAB,WAC and WAD.The correct relation between these parameters are:
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a
EAB=EAC=EAD,WAB>0,WAC=0,WAD<0
b
EAB>EAC>EAD,WAB
c
EAB0,WAC>WAD
d
EAB=EAC0,WAC=0,WAD<0
answer is A.
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Detailed Solution
Clearly EA=EB=EC as change in temperature is sameWAC=0∵V remains same WAB> 0 ∵V Increases WAD<0 ∵V Decreases