Two beams of light having intensities I and 4I interfere to produce a fringe pattern on a screen. The phase difference between the beams is π2 at point A and π at point B. Then, the difference between resultant intensities at A and B is
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a
5I
b
4I
c
3I
d
7I
answer is B.
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Detailed Solution
Iϕ=I1+I2+2I1I2cosϕ Here, I1=I and I2=4I At point A, ϕ=π2 ∴IA=I+4I+0=5I At point B, ϕ=π ∴IB=I+4I−4I=I hence. IA−IB=4I