Two different monochromatic beams of same intensity hit a screen. If number of photons hitting the screen by beam A is twice than by B. Then fA : fB is
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a
1 :1
b
2:1
c
1:2
d
3:2
answer is C.
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Detailed Solution
Intensity is energy incident per unit area per unit time. As the intensities are same and A is emitting double the photons than B for the same energy that means B should be having double the frequency than A.fA:fB=1:2