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Q.

Two identical containers each of volume V0 are joined by a small pipe. The containers contain identical gases at temperature T0 and pressure P0. One container is heated to temperature 2T0 while maintaining the other at the same temperature. The common pressure of the gas is P and n is the number of moles of gas in container at temperature 2T0.

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a

P=2P0

b

P=23P0

c

n=2P0V03RT0

d

n=3P0V02RT0

answer is C.

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Detailed Solution

n1+n2=n11+n21P0V0RT0+P0V0RT0=PV0RT0+PV0R2T02P0V0RT0=PV0RT032⇒P=4P03from ideal gas equation PV = nRT4P03V0=n21R2T0

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Two identical containers each of volume V0 are joined by a small pipe. The containers contain identical gases at temperature T0 and pressure P0. One container is heated to temperature 2T0 while maintaining the other at the same temperature. The common pressure of the gas is P and n is the number of moles of gas in container at temperature 2T0.